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Linear Algebra Q: In RREF form 1 0 1 5 0 1 0 -1 0 0 0 0 so x+z=5 and y=-1....is z a free variable? how would i write up the soln to this matrix?
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what was wrong with the other solution?
since the last row is all zeros, there is an infinite number of solutions; 0 always = 0
yes, the 3rd variable is free so you would have an homogenous part and a particular part
z<-1,0,1> + <5,-1,0> would be parametric solution
so, would z=t and then x=5-t? than kyou for ur response....if u posted previous respnses,....i did n't see them. apologies
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thats one way to write it up yes :)
much appreciated
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