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Mathematics
OpenStudy (anonymous):

Anyone have an idea to this question, at first I thought it was a simple definite integral question, but it's not. I've posted a pic of the question! http://tnypic.net/4a46c.jpg

OpenStudy (anonymous):

I did that originally, however the answer is wrong. I have the solution to it but it still doesn't make sense to me. I'll post it now

OpenStudy (anonymous):

dv/dt=1/(a+bv) so dt=(a+bv)dv giving by integration t=av+(b/2)v^2+C but v=0 at t=0 so C=0 therefore t=av+(b/2)v^2

OpenStudy (anonymous):

I don't understand how you integrated dt=(a+bv)dv to get t=av+(b/2)v^2 : [ Are you integrating each term one by one?

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