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OpenStudy (anonymous):
1/sinx-1/cscx=cscx-sinx
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OpenStudy (anonymous):
1/sin(x) = csc(x). csc(x) = 1/sin(x) by definition.
OpenStudy (anonymous):
Therefore 1/csc(x) = sin(x).
hero (hero):
1/sinx-1/cscx=cscx-sinx 1/sinx - sinx = 1/sinx - sinx true
OpenStudy (anonymous):
Thank you!
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