Question

(squaredrootof)x-5=(squaredrootof)x-1 [the -1 is not inside the squaredroot) :)

Answer 1

square both sides
you have to FOIL the right side

Answer 2

uhhh.... i need help with that :///

Answer 3

\[\sqrt{x-5}=\sqrt{x}-1\]\[(\sqrt{x-5})^2=(\sqrt{x}-1)^2\]v-------------^\[(\sqrt{x}-1)(\sqrt{x}-1)\]FOIL
\[(x-\sqrt{x}-\sqrt{x}+1)\]\[(x-2\sqrt{x}-1)\]\[x-5=x-2\sqrt{x}+1\]-x -1 -x -1
\[-6=-2\sqrt{x}\]/-2 /-2\[3=\sqrt{x}\]\[(3)^2=(\sqrt{x})^2\]\[9=x\]Finished!!!

Answer 4

woah.. id nt get the foil.. why woudl (sqrdrt) of x multiplied by the same thing give x?

Answer 5

I forget the name of the actual rule. But simply it's\[(x^2)(x^3)=x^5\]What you do is take the exponents and add them together.\[\sqrt{x}=x ^{1/2}\]Therefore\[(\sqrt{x})(\sqrt{x})=(x ^{1/2})(x ^{1/2})\]Which then makes\[(x ^{1/2})(x ^{1/2})=x^1\]or x.

Answer 6

oh. haha. sorry :)
and i don't get the x-1-x-1 part.. :(

Answer 7

\[(x ^{a})(x ^{b})=x ^{a+b}\] That's the rule.

Answer 8

I'm subtracting x and 1 from each side.

Answer 9

ooohh... i see it now:)
can you repeart that last part? after the little isue i just did? my computer won't show anything after that. :(

Answer 10

after the -x-1-x-1?

Answer 11

yes.

Answer 12

\[x-5=x-2\sqrt{x}+1\]-x -1 -x -1\[-6=-2\sqrt{x}\]/-2 /-2\[3=\sqrt{x}\]\[(3)^2=(\sqrt{x})^2\]\[9=x\]

Answer 13

what do the /-2/-2 stand for?

Answer 14

Divide by -2 on both sides.

Answer 15

okay. :)

Answer 16

I was taught "The Granny Rule: Granny's are fair, what they do to one chile they do to the other." Same with algebra, what you do to one side of the equation you have to do to the other.

Answer 17

*child*

Answer 18

mahaha:) that's a good way to remember it:D