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Solve for x: sin^(-1)(1-x)-2sin^(-1)x= π/2
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sin^(-1) is inverse sine, right?
\[\sin^{-1}(1-x)-2\sin^{-1}x= π/2\]
It is sin inverse
Wolframalpha gives the answer as x=0
http://www.wolframalpha.com/input/?i=inverse+sine+%281-x%29-2+inverse+sine+x%3D+%CF%80%2F2
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Steps please?
take sin inverse (1-x) as alpha and sin inverse x as theta sin(alpha-2theta)=sin(pi/2) sinalphacos2thta-cosalphasin2theta=sinpi/2 apply the corresponding values then u vl get the answr
ok i will try ThanQ ;) here comes your medal
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