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OpenStudy (anonymous):
a fair dice is being rolled.what is the probability that a six appears in at most in at most n attempts?
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OpenStudy (king):
hmmm. is it 1/6?
OpenStudy (anonymous):
once in 1 attempt = 1/6 twice in two attempts = 1/6 * 1/6 thrice in three attempts = 1/6 *1/6 *1/6 n in n attempts = (1/6)^n
OpenStudy (king):
oh ok!
OpenStudy (anonymous):
okay so it gets magnified according to the attempts
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