Ask your own question, for FREE!
Mathematics
OpenStudy (anonymous):

" I need help " Evaluate (n+2)!/(n-1)! leaving your answer in factorized form.

OpenStudy (anonymous):

Please guys !

OpenStudy (zarkon):

(n+2)(n+1)n

OpenStudy (anonymous):

Ex cause me , How ?

OpenStudy (zarkon):

(n+2)!=(n+2)(n+1)(n)(n-1)(n-2)...(3)(2)(1) =[(n+2)(n+1)(n)]*(n-1)!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!