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OpenStudy (anonymous):
" I need help " Evaluate (n+2)!/(n-1)! leaving your answer in factorized form.
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OpenStudy (anonymous):
Please guys !
OpenStudy (zarkon):
(n+2)(n+1)n
OpenStudy (anonymous):
Ex cause me , How ?
OpenStudy (zarkon):
(n+2)!=(n+2)(n+1)(n)(n-1)(n-2)...(3)(2)(1) =[(n+2)(n+1)(n)]*(n-1)!
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