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Mathematics
OpenStudy (anonymous):

how do you find the short leg in a 60-30-90 triangle, if the give you the long leg

OpenStudy (hoblos):

short leg = long leg/2

OpenStudy (anonymous):

OK THANK YOU SO MUCHHHH

OpenStudy (hoblos):

MY PLEASURE XD

OpenStudy (anonymous):

im sorry sir but thats wrong... that would be the hypotenuse. Because shortleg times 2 = hypotenuse. and short leg times sqrt3= long leg. and i just frekin found out how...wow i fail...it is short leg/sqrt3 i think?

OpenStudy (anonymous):

i mean long leg/sqrt3

OpenStudy (anonymous):

im confuseddd

OpenStudy (hoblos):

sorrrry i thought you mean the hypotenuse by <the long leg> im really really sorry yeah what you said is right :s

OpenStudy (anonymous):

so 27/sqrt3 would be what?

OpenStudy (hoblos):

27/sqrt3 = 27sqrt3/3 = 9sqrt3 = 15.588

OpenStudy (anonymous):

i thought so..thankssss!!!!1

OpenStudy (anonymous):

im a fan!;p

OpenStudy (anonymous):

There are many ropes keeping a hot air balloon from floating away before a balloon race. One of these ropes is fixed to the ground at a 45° angle. Another is fixed to the ground at a 30° angle. If the hot air balloon is 18 feet off the ground, what is the distance between the ground directly underneath the balloon and the second rope rounded to the nearest hundredth of a foot?

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