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Mathematics 8 Online
OpenStudy (anonymous):

help with algebra plz

OpenStudy (anonymous):

\[\sqrt[11]{8}+\sqrt[6]{12}-\sqrt[5]{2}\]

OpenStudy (anonymous):

d sorry can u mention which root is over 12 and 2

OpenStudy (anonymous):

yes :) 6 for 12 and 5 for 2

hero (hero):

put the roots in fraction form. That might help

OpenStudy (anonymous):

its 1.5724

OpenStudy (anonymous):

ohyou didnt have to give the answer :P i just wanted help with solving it :)

hero (hero):

She wants actual steps

OpenStudy (anonymous):

i just dont know how to solve this with the number superscripted on the square root.

OpenStudy (anonymous):

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OpenStudy (wasiqss):

u want answer in decimal or fraction form cox this cant b evaluated in fraction form

OpenStudy (anonymous):

Okay you want a reduce form under radical right?

OpenStudy (anonymous):

fibonacci girl sorry ......just saw that you wanted the steps also

OpenStudy (anonymous):

radical form :)

OpenStudy (anonymous):

and i dont want to you guys to do the work for me, i just want to know how to do this. it is driving me crazyy

OpenStudy (anonymous):

fibonacci girl do you know how to use logs

OpenStudy (anonymous):

That's admirable :) Okay tell me do you know indices?

OpenStudy (wasiqss):

hey we can make under root 2 common,

OpenStudy (anonymous):

no :/

OpenStudy (anonymous):

No logarithm needed, IMO.

OpenStudy (anonymous):

Okay do you know that \(\huge \sqrt[a]{b} = b^\frac 1a \) ?

OpenStudy (anonymous):

oh yeah!! i learned that in precalc like 2 months ago!

OpenStudy (anonymous):

Good, so now it's time to apply what you learned, lets see, your problems is \( \sqrt[11]{8}+\sqrt[6]{12}-\sqrt[5]{2} \) lets assume the first term first \( \large\sqrt[11]{8} = 2^ \frac 3{11} \) can you follow this?

OpenStudy (anonymous):

yes i can :)

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