Question

integrate tan^2xdx=?????

Answer 1

\[ 1 + \tan^2 x = \sec^2 x \]
Hence
\[ \int \tan^2 x dx = \int (\sec^2 x - 1) dx \] = ...

Answer 2

tan^2(x) = sec^2(x) - 1

Sub u = tan(x)
and du = sec^2(x)dx

Answer 3

tnx :)

Answer 4

so on?