Question

Solve the linear system by the method of elimination.
x+4y-z=12
3x+8y-2z=4

Answer 1

multiply first equation by -3 and assum by second

-3x-12y+3z=-36
3x+8y-2z=4
-----------------
0 -4y +z=-32

Answer 2

multiply first equation by -2 and assum with second

-2x-8y+2z=-24
3x+8y-2z=4
-----------------
x 0 0 =-20

x=-20


-20+4y-z=12
-60+8y-2z=4

4y-z=32
8y-2z=64 / divide by 2

4y-z=32
4y-z=32
--------
8y-2z=64

Answer 3

Thanks so much for your help!