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3cosx+9=7 slove for x
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Subtract 9 on both sides Then divide both sides by 3
yes i got 131.8 another on ew
plz say plz
\[\cos(x)=\frac{-2}{3}\] \[\cos(x)=\cos(x+2 \pi n)\] \[\text{ so we have } \cos(x+2 n \pi)=\frac{-2}{3}\]
Now take arccos of both sides
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\[x+2 n \pi=arc \cos(-\frac{2}{3})\]
to solve for x subtract 2npi on both sides
@myin on this..i have to learn this for ACT, but how would u solve it exactly? what does cos mean?
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