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What are the polar coordinates for the point (1,-2) i got r = 5 but theta = arctan -2?
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\[r=\sqrt{5}\]
yeah i got that far
and yes, in this case \[\theta =\tan^{-1}(-2)\] because you are in quadrant 4
okay so arctan(-2) is correct?
yes. it is always the case that \[\tan(\theta)=\frac{b}{a}\] but it is not always the case that \[\theta=\tan^{-1}(\frac{b}{a})\]
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because arctan only returns answers in \[[-\frac{\pi}{2},\frac{\pi}{2}]\]so you need to be careful about what quadrant you are in
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