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What value is added to both sides of the equation x2 – 8x = –10 in order to solve by completing the square? a. –8 b. 16 c. –4 d. 4 I think its a, am i right?
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One half of 8 is 4 and 4 squared is 16 so add 16 to both sides.
wait what
what mertsj said, with exactly that reasoning
forget the number on the right hand side, it is irrelevant
you have \[x^2-\color{red}{8}x\] \[\frac{8}{2}=4, 4^2=16\] add 16 to both sides get \[(x-4)^2=-10+16=6\]
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you should think it in english exactly as mertsj wrote it half of 8 is 4, 4 squared is 16
oh i see, i guess i understand better with visual. Thanks a ton!
\[x^2+12x=-5\] half of 12 is 6, 6 squared is 36 \[(x+6)^2=-5+36\] etc
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