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Solve. x^2 – 4x = 0 a. x = 0 and x = –4 b. x = 2 and x = –2 c. x = 4 and x = 0 d. x = 0
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do you know how to factor x^2-4x
yes, its x - 4, right?
\[x(x-4)\] since \[x(x-4)=x \cdot x - x \cdot 4=x^2-4x\]
so we have the following we need to solve \[x(x-4)=0\] which implies x=0 or x-4=0
ok
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and x = 4?
is it?
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