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Mathematics 23 Online
OpenStudy (anonymous):

HELP WITH TRIANGLES AND HOW TO FIND AREA

OpenStudy (anonymous):

Area=1/2 * Base * Height

OpenStudy (anonymous):

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OpenStudy (mertsj):

A=1/2absinC

OpenStudy (anonymous):

i dont know how to do this one

OpenStudy (anonymous):

\[a^2+(3.6)^2=5^2\] \[a^2+12.96=25\] \[a^2=12.04\] \[a=\sqrt{12.96}\] a=3.47

OpenStudy (anonymous):

That is your height. Now use A=1/2BH

OpenStudy (anonymous):

IM stuck AGAIN.

OpenStudy (anonymous):

\[A=1/2*7.2*3.47\] A=12.492 units^2

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