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OpenStudy (anonymous):
what is this limit
\[\lim_{x \rightarrow \pi/2}(xcosx)\]
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OpenStudy (anonymous):
\[\lim_{x \rightarrow \pi/2}(xcosx)\]
OpenStudy (mertsj):
0
OpenStudy (anonymous):
mertsj do you mind demonstrating that please?
OpenStudy (mertsj):
pi/2times cospi/2=pi/2times 0 = 0
OpenStudy (anonymous):
ok thanks would you mind helping me with this one also
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OpenStudy (anonymous):
\[\lim_{x \rightarrow -7}(x^2 + 10x + 21/x + 7)\]
i've got -98/0. i dont know what to do from there
OpenStudy (mertsj):
You can't divide by 0 so divide numerator so another approach is needed.
OpenStudy (mertsj):
Factor and reduce first
OpenStudy (anonymous):
ok i was thinking along the lines as approach -7 from left and right
OpenStudy (anonymous):
(x+7)(x+3)/(x+7)...so the x + 7 cancels and im left with x + 3
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OpenStudy (mertsj):
yes
OpenStudy (mertsj):
Now replace the x with -7
OpenStudy (anonymous):
i see.
OpenStudy (anonymous):
i have this one that is somewhat similar but you end up with 0/0
\[\lim_{x \rightarrow 1}(x^2 - 4x + 3/ x^2 + 2x -3)\]
OpenStudy (anonymous):
same approach again right? factor and reduce?
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OpenStudy (mertsj):
yes
OpenStudy (anonymous):
(x-3)(x-1)/ (x-3)(x+1)...?
OpenStudy (anonymous):
is that the right structure
OpenStudy (mertsj):
|dw:1326943979278:dw|
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