Question

Solve the equation for 0≤x<2π
» 2sin²2x=1

Answer 1

2sin²2x = 1

divide both sides by 2
sin²2x = 1/2

take the sq roots of both the sides
sin2x = -1/√2 or sin2x = 1/√2

Take the inverse sine of both sides:
2x = -π/4 or sin2x = 1/√2

divide both sides by 2
x = -π/8 or sin2x = 1/√2

take the inverse of sine of both sides
x = -π/8 or 2x = π/4

divide both sides by 2
x = -π/8 or x = π/8...