Given the domain {-5, 2, 3}, what is the range for the relation 16x + 4y = 12?

A) {-1, 5, 6}

B) {-23, 5, 9}

C) {-17, 11, 15}

D) {23, -5, -9}

thanks!:)

Question

Given the domain {-5, 2, 3}, what is the range for the relation 16x + 4y = 12?

A) {-1, 5, 6}

B) {-23, 5, 9}

C) {-17, 11, 15}

D) {23, -5, -9}

thanks!:)

dumbcow · Answer

solve for y, then plug in x-values from domain

anonymous · Answer

Answer =option(D)

{23 , -5 , -9}

anonymous · Answer

16x + 4y = 12

solve for y
    16x + 4y = 12
   -16x          -16x
-------------------
             4y  = 12 - 16x 
(divide by 4 on both side)

               y  = 3 - 4x 

Now plug the x-values(that is domain value) to find y (that is range)

plug x=-5     plug x=2        plug x=3
y=3-4(-5)     y=3-4(2)    y=3-4(3)
y=3+20        y=3-8         y=3-12
y=23             y=-5         y=-9

Therefore,Range={23,-5,-9}

anonymous · Answer

I hope that you got it