Question

Given the domain {-5, 2, 3}, what is the range for the relation 16x + 4y = 12?

A) {-1, 5, 6}

B) {-23, 5, 9}

C) {-17, 11, 15}

D) {23, -5, -9}

thanks!:)

Answer 1

solve for y, then plug in x-values from domain

Answer 2

Answer =option(D)

{23 , -5 , -9}

Answer 3

16x + 4y = 12

solve for y
16x + 4y = 12
-16x -16x
-------------------
4y = 12 - 16x
(divide by 4 on both side)

y = 3 - 4x

Now plug the x-values(that is domain value) to find y (that is range)

plug x=-5 plug x=2 plug x=3
y=3-4(-5) y=3-4(2) y=3-4(3)
y=3+20 y=3-8 y=3-12
y=23 y=-5 y=-9

Therefore,Range={23,-5,-9}

Answer 4

I hope that you got it