Question

Write the equation of the line that is perpendicular to the line y = 3/2x + 4 and passes through the point (-6, 3).
Answer
y = 3/2x - 1
y = 3/2x + 3
y = - 2/3x - 1
y = - 2/3x + 3

Answer 1

perpendicular m2=-1/m1=-1/(3/2)=-2/3
y-yo=m(x-x0)
y-3=-2/3(x+6)
y=-2/3x-1