plzz help ... Solve each polynomial equation 1. 15x^3-119x^2-10+16=0 2. x^3-14x^2+47x-18=0 3. 5x^3-27x^2-17x-6=0
I notice that these are all cubics. So I would first try to factor by grouping and if that doesn't work, then try synthetic division.
thank u
how do i do synthetic division with no divisor or watever its called?
Let's look at the first one.. The constant term is 16 and the coefficient of the x^3 term is 15. So the possible rational roots are the factors of 16 over the factors of 15 Use those for your "shelf" numbers in the synthetic division process. If you get a remainder of 0, that number is a root.
So the possible rational roots are:\[\pm1, \pm2,\pm4,\pm8,\pm16,\pm1/3,\pm1/5,\pm1/15,\pm2/3,\pm4/3,\pm8/3,\pm16/3,\pm2/5,\pm4/5\]
and so on
so i take the numbers and do what?
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