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Mathematics 24 Online
OpenStudy (anonymous):

Evaluate (n+2)!/(n-1)! leaving your answer in factorized form.

OpenStudy (ash2326):

we know n!=n*(n-1)! (n+2)!=(n+2)(n+1)(n)(n-1)! now (n+2)!/(n-1)!=(n+2)(n+1)(n)(n-1)!/(n-1)! we get (n+2)!/(n-1)!= (n+2)(n+1)(n)

OpenStudy (anonymous):

Thank you .

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