Question

An airplane travels 900 miles from Houston to Miami in 6 hours against the wind. On its return trip, with the wind, it only takes 5 hours. Find the rate of the airplane with no wind. Find the rate of the wind.

Answer 1

Let the ground speed be x
And the wind speed be y
AGAINST WIND
Distance = 900 miles.
Distance = Rate * time
900= (x-y)*6
WITH WIND
Distance = 900 miles.
Distance = Rate * time
900= (x+y)*5
6x-6y=900
x-y= 150
5x+5y=900
x+y=180
x-y= 150
x+y=180
2x=330
x= 165 mph = ground speed ( With no wind )
y= 15
The ground speed of the plane is 165 mph and wind speed = 15 mph

Answer 2

Thanks

Answer 3

No problem :D

Answer 4

How Did You get x-y= 150 ?

Answer 5

that's just how you find speed without wind resistance.
900 = (x-y) *6
900/6 = x-y
150 = x-y

Answer 6

How Did You Get 2x=330 ?

Answer 7

Never mind Thanks

Answer 8

so what was the answer?

Answer 9

x=165 mph
y=15 Wind Speed

Answer 10

I'm sorry I didn't answer I'm doing my homework

Answer 11

Its Okay I Believe I Know How To Do This Now :D

Answer 12

Glad I helped :D