Question

what is the equation of the tangent line to the graph of y = (3e^2x) +1 at the point (0,4)

Answer 1

y=6x+4

Answer 2

y=(3e^2x) +1 , y'=6e^2x

When x=0, y'=6 <--- this is the slope of the tangent line

y=mx+c
y=6x+c

When x=0, y=4
c=4

The equation of the tangent line is y=6x+4