Question

find the equation of the tangent to y=logx at the point where x=e^2

Answer 1

log as in base 10 or base e?

Answer 2

\[L_{tan} = f'(e^2)x -f'(e^2)e^2 + log(e^2)\]

Answer 3

now the only thing to do is define what log represents since it can go either way apparently

Answer 4

YUP :).

Answer 5

http://mathworld.wolfram.com/Ln.html

Answer 6

wait so should the equation look like y-2log =1/e^2 (x-e^2)

Answer 7

*y-2loge