Question

find removable discontinuity


f(x)=(x^2-7x-8)/(x^3+64)

Answer 1

factor the denominator as the sum of two cubes

Answer 2

and the numerator as
\[(x+1)(x-8)\] then you can cancel the
\[x-1\] so the discontinuity is "removable" because by factoring and canceling you can remove it