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simplify : x^2(y^2*z^3)^-2/y^3(xz^-3)^2
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um...... Wait
\[\huge \frac{x^2y^{-4}z^-{6}}{y^3x^2z^{-6}}\] Can you do now ?
Actually, no . It's so confusing.
How did you do the last result please ?
Remember :\[\huge x^m \times x^n = x^{m+n}\]\[\huge x^{-m}= \frac{1}{x^m}\]
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\[\huge \frac{x^2(y^2*z^3)^{-2}}{y^3(xz^{-3})^2}=\frac{x^2 (y^2)^{-2}(z^3)^{-2}}{y^3(x)^2(z^{-3})^2}\]
I have to say " thank you a lot Diyadiya "
You still have to simplify it You're Welcome (:
atleast give her medals!!!
Where are you ? I need your help again .
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Sorry " I forgot to click on Good answer "
No problem your other question has been answered by ishaan :)
but it's not clear answer .
ok wait
sorry i gtg now ask in the chat for someone to help you out :)
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okay .
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