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OpenStudy (anonymous):
Solve: 25=48T^2
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OpenStudy (anonymous):
T^2=25/48, \[T=\pm \sqrt{25/48}\] \[T=\pm(5/4\sqrt{3}) (4\sqrt{3}/4\sqrt{3})=\pm(5/12) \sqrt{3}\]
jhonyy9 (jhonyy9):
T=+/- sqrt(25/48)=+/- sqrt(25/(16*3))=+/- (5/4)((sqrt3)/3) =+/- (5sqrt3)/12
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