Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (anonymous):

Solve: 25=48T^2

OpenStudy (anonymous):

T^2=25/48, \[T=\pm \sqrt{25/48}\] \[T=\pm(5/4\sqrt{3}) (4\sqrt{3}/4\sqrt{3})=\pm(5/12) \sqrt{3}\]

jhonyy9 (jhonyy9):

T=+/- sqrt(25/48)=+/- sqrt(25/(16*3))=+/- (5/4)((sqrt3)/3) =+/- (5sqrt3)/12

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!