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OpenStudy (anonymous):
Use the sum of cubes to factor. x^3+125
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OpenStudy (anonymous):
x^3 + 125 = x^3 + 5^3 Use the a^3 + b^3 identity to factor it now.
jhonyy9 (jhonyy9):
- so i think that will be \[(x+5)(x ^{2}-5x +25)\]
OpenStudy (anonymous):
Yes.
jhonyy9 (jhonyy9):
thank you
OpenStudy (anonymous):
thanks!!!
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