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Mathematics 11 Online
OpenStudy (pokemon23):

how do you find an a percent of an item

OpenStudy (pokemon23):

Imagine you need to buy a video game system for 169,99 dollars and you get a coupon for 40 % percent how much do you have to pay?

OpenStudy (pokemon23):

is their like a mathematical term

hero (hero):

Actually, the general formula is x - %x = y x = original price y = new price

OpenStudy (pokemon23):

basically the percent of change

hero (hero):

169.99 - .40(169.99) = y

OpenStudy (anonymous):

assume a value is 100% of itself, splitting it into 100 parts will make each part be 1%, so devide by 100. then you have the value of 1 percent and if you need 40 you multiply it with that

hero (hero):

Don't mix things up. This is not percent change

OpenStudy (pokemon23):

oh

hero (hero):

Percent change has its own formula

hero (hero):

The formula I gave you is the "Discount Price Formula"

OpenStudy (pokemon23):

ok thanks basically I just got like 2 packs of coupons for online shopping discounts

OpenStudy (pokemon23):

for free :D

hero (hero):

Free coupons, lol They better be free or else you're not getting a deal

OpenStudy (pokemon23):

you want one

hero (hero):

No, lol

hero (hero):

I have my own strategies for getting discounts

OpenStudy (pokemon23):

you might buy something special for you know who XD

OpenStudy (pokemon23):

online shopping

hero (hero):

The gift for my you know who doesn't involve physical gifts ormoney

OpenStudy (pokemon23):

LOL HERO

OpenStudy (pokemon23):

anyways I will probably might used this to get a headset

hero (hero):

good

OpenStudy (asnaseer):

Another way of calculating that would be to say: Discount of 40% means you pay (100-40)% = 60% So 60% of 169.99 = .60 * 169.99

hero (hero):

Nice. Asnaseer, you're always full of great insight and perspective.

OpenStudy (asnaseer):

thx Hero - you too...

hero (hero):

Is there a general formula for that approach? You using x and y as variables?

OpenStudy (asnaseer):

If price is P and discount is D% then you would pay (100-D)*P/100

hero (hero):

:D

OpenStudy (pokemon23):

Thanks guys

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