Express the area of each figure as a monomial. How would I solve 7x^4 if the formula is s^2 Steps on how you got the answer are appreciated, it'll help me on my test. Thanks.
are you saying we have a square and each side has length 7x^4?
if so then you do \[(7x^4)^2=7^2x^{4 \cdot 2}\]
\[=49x^8\]
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not sure if the fact that it's a circle and not a square would affect the outcome of the answer..
What do you mean by "each figure"? the circle?
Yes.
So, you want the area of the circle in terms of x?
Honestly, I have no idea what this question is asking me to do.. It just tells me to express the area of the figure as a monomial.
but the figure they give you is a circle right?
\[A=\pi r^2=\pi (7x^4)^2\]
area of a circle is pi times radius squared
the radius in the circle you drew above is 7x^4
so i replaced r with 7x^4
you beat me to it myin
\[A=\pi(7^2 \cdot x^{4 \cdot 2})\] :)
\[A=49x^8 \pi\]
since 7^2=49 and x^(4 times 2)=x^8
Thank you :)
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