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If the sides of a square are lengthened by 5m, the area becomes 196cm^2. Find the length of a side of the original square.
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\[A=s^{2}\] for a regular square For this square, \[A=(s+5)^{2}\] so \[196=(s+5)^{2}\]
(x+5)^2=196 x+5=14 x=9
So if s or x = 9, then to find the length of a side of the original square I need to plug 9 into A=s^2, which would be A=9^2, A=81?
No. 9 is the side of the original square. Notice the equation in relation to the problem. It says the side of the original square was increased by 5 so x+5 means the original side with 5 added. So x is the original side.
Ok, I understand. Thank you.
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