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Using trapezoid GHIJ, solve for x. A.3 B.4 C.8 D.9 (i will post the photo in a sec)
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9...is it correct...
ill try, thank you :)
Set up the equation as\[h(x+4+17)=h(17+3x-2)\]\[x+4=3x-2\] and solve for x.
\[x + 4= 3x -2 \] \[x -3x = -4 -2\] \[-2x = -6\] \[x = 3\]
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