Question

find three consecutive even numbers so that the sum of the first and third numbers is 22 less than then three times the second number

Answer 1

First number = x
Second number = x+2
Third number = x+4
\[(x)+(x+4) = 3(x+2)-22\]
\[2x + 4 = 3x+6 - 22\]\[-x+4 = -16\]\[x = 20\]

Answer 2

So 20, 22, 24

Answer 3

thanks!