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f(2)=6, f'(2)=-4, and f''(2)=2. What is d^2(f^3(x))/dx^2 at x=2? PLEASE EXPLAIN!
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f(2)=6 f^3(2) = 6^3 = 216
the position at x=2 is 6 the slope at x=2 is -4 the concavity at x=2 is cave up is what i think I can parse
I have this one somewhere
whew!! good lol
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