Question

Choose the equation of the line passing through the point (6, -2) and parallel to y = x + 7.

y = x + 8

y = x - 4

y = x + 4

y = x - 8

Answer 1

parallel lines have same homogenous parts and differ by the particular part

Answer 2

keep the x and lose the constant; then calibrate a new constant with the given point

Answer 3

y = x + 7

y = x + c ; use(6,-2)

-2 = 6 + c

-8 = c

y = x-8

Answer 4

y=ax+b
if lines are parallel then they have the same ``a``
so y=x+7 a=1

y_2=1x+b if a point on a line then (6,-2)=(x,y)
-2=1*6+b
b=-8
y_2=x-8