Question

Teach me in solving this inequality.

Answer 1

|2x−11|−2>4x+7

Answer 2

I know how to solve equations. But I just don't know how to solve if it has absolute value sign. Teach me please. :)

Answer 3

x < 1/3

Answer 4

how?

Answer 5

Teach me please and give me another example after teaching it. so that I can practice. and you will going to check it if I am right.

Answer 6

To remove the modulus sign we write \[|2x -11|\] as \[\sqrt{2x - 11}^2\]

Answer 7

Why is that?

Answer 8

http://www.mathmotivation.com/lectures/Inequalities.pdf

Answer 9

To remove any modulus sign write
\[\left| ax + b \right| = (\sqrt{ax + b})^2\]

Answer 10

Could you solve it step by step? and what is the reason behind To remove any modulus sign write

Answer 11

\[\left| ax + b \right| = (\sqrt{ax + b})^2\]

Answer 12

|2x−11|−2>4x+7
|2x−11| > 4x +9 then
2x-11 > 4x +9 OR 2x-11 < -(4x+9)
-2x > 20 2x -11 < -4x -9
x<-10 6x < 2
x<1/3

Answer 13

please explain

Answer 14

rules:
if |x| < a then -a<x<a
if |x| >a then x>a OR x<-a

Answer 15

you apply the second rule here

Answer 16

Thanks!

Answer 17

What if it is "="

Answer 18

if |x| = a then x=a OR x=-a