Question

how to find the equation of diameter..? of a circle..whose equation is x2+Y2-12x+4Y+6=0

Answer 1

could u explain it clearly

Answer 2

You need to complete the square for both the x and y values within the equation.

Answer 3

mark..we have to find the equation of diameter?

Answer 4

can anyof u tell me how to find the equation of diameter?

Answer 5

You need to put the equation in standard form first.
\[x^2+y^2-12x+4y+6=0\]
\[x^2-12x+y^2+4y+6=0\]
\[(x^2-12x)+(y^2+4y)+6=0\]
\[(x^2-12x +36-36)^2+(y^2+4y+4-4)+6=0\] this is the completing the square part
\[(x^2-12x +36)^2-36+(y^2+4y+4)-4+6=0\]
\[(x^2-12x +36)^2+(y^2+4y+4)+38=0\]
\[(x-6)^2+(y+2)^2+38=0\]

Answer 6

oops, thte +38 should be -34

Answer 7

Once you move the -34 over, it means the radius is sqrt(34)

Answer 8

okay here is the formulae for the diameter

Answer 9

hey is it area or perimeter

Answer 10

its diameter of circle

Answer 11

yeah so the diameter is 2x the square root of 34

Answer 12

okay formulae of a diameter
d=2xr

Answer 13

but we hav to find the equation not only diameter

Answer 14

oh first we have to slove it right

Answer 15

hmm..yup

Answer 16

hey razor r u on fb?

Answer 17

yeah

Answer 18

wud u lyk 2 b mah frnd..?

Answer 19

okay but i am a boy

Answer 20

uhh..y r u tellng mee lolz..!! it dsnt seem scary 2 mee

Answer 21

oh lets talk some other time okay u have a equation to do

Answer 22

yea..i got it

Answer 23

dont worry jimmyrep is coming

Answer 24

whoz he?

Answer 25

comeon u would know

Answer 26

Equation x2+Y2-12*x+4*Y+6=0 solved for x
x = (Y2+4*Y+x2+6)/12

Answer 27

so the answer is

Answer 28

Equation x2+Y2-12*x+4*Y+6=0 solved for x
x = (Y2+4*Y+x2+6)/12