Question

A particle of mass m fall freely from rest under gravity for a time 1/2k.how find the distance it has fallen and the speed attained.

Answer 1

s=ut+1/2 at^2
u is the initial velocity t
a= acceleration here it's gravity
t=time
s=1/2* 9.8*t^2
substitute t to find the distance covered

Answer 2

for speed v=u+at
u=0
v is the final velocity
v=9.8*t
substitute t to find the velocity

Answer 3

s=g/8k2 and v=g/2k isn't?

Answer 4

yeah