In sinθ/θ, I see that as θ approaches zero both approach zero however what I do not see proven is that sinθ approaches zero faster than θ.

Question

In  sinθ/θ, I see that as θ approaches zero both approach zero however what I do not see proven is that sinθ approaches zero faster than θ.

anonymous · Answer

We often prove the limit as theta is approaching zero of the sine of theta divided by theta is equal to one using the Squeeze Theorem or sometimes called the Sandwich Theorem.

anonymous · Answer