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Solve. \[7^{x-4} = 7 ^{4x+7}\]
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just set the exponents equal and solve for x x-4=4x+7
i get -11/3 and thats not one of the choices.
Subtract x on both sides -4=3x+7 Subtract 7 on both sides -11=3x and divide by 3 on both sides -11/3=x I agree with you answer Is it perhaps written in decimal form or as a mix fraction?
\[x=-\frac{3(3)+2}{3}=-(\frac{3(3)}{3}+\frac{2}{3})=-(3+\frac{2}{3})=-3\frac {2}{3}\]
the answers are A: x = -4, B: x=2/3, C:x=-12/5, D: x=4
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The question is correct, right?
it is \[-\frac{11}{3}\] for sure
yep unless the problem is wrong
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