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what is the simplified form of (4x^2-20x+25)/(2x-5)
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Factor the numerator and cancel.
(4x^2-20x+25)/(2x-5) ((2x-5)(2x-5))/(2x-5) ... Note: this is a perfect square 2x-5
\[\frac{4x ^{2}-20x+25}{2x-5}=\frac{(2x-5)(2x-5)}{2x-5}=2x-5\]
so if i was given the same choices as last time, its still not equal to 5/2?
yes to avoid dividing by zero
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