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Restriction? (x+8)/(x^2 +4x-32) i think it's x=4?
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the denominator is not zero
12/0? undefined to me..
so u got two answers (as it is a quadratic )
This is the question. (x+8)/(x^2 +4x-32)
(x^2 +4x-32) is not zero
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restriction=undefined?
So restriction?
Idk how to find it's restriction.
(x^2 +4x-32) = 0 (x + 8) (x-4) = 0 x cannot be equal to -8 or 4
Oh, okay, so
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Ah, Righto!
Restriction = \[x \ne -8 , x \ne 4\]
yes
Thankyou!! ^_^
yw :D :P
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