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Trig question...cos ( 90 + Q) is it equal to + sin Q since it's in quadrant 2 ? Or is it -sin Q since cos is negative in quadrant 2 ?...:s
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well, it is negative if Q is between 0 and 90
err, 0 and 180 .... doesnt really leave the left side does it till 270
but yeah, think of it like tuning the graph so that y is in place of the x axis
cos(t-90) = sin(t)
It's cos ( 90 + Q) not 90 - Q tho :P
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or t - 90 as you said
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