Question

3^x = (1/9)^3

What is the value of x?

Answer 1

\[3^x=(\frac19)^3\]
\[3^x=(9^{-1})^3=9^{-3}=(3^2)^{-3}=3^{-6}\]
x=-6

Answer 2

How did you get the 3^2?