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If m ≤ f(x) ≤ M for a ≤ x ≤ b, where m is the absolute minimum and M is the absolute maximum of f on the interval [a, b], then
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\[m(b-a) \le \int\limits_{a}^{b} f(x) dx \le M(b-a)\]
Estimate the smallest and largest value for \[\int\limits_{5\pi}^{6\pi} (5x - 10sinx) dx\]
f(x)=(5/2 (x^2+4 cos(x)) you just need to substitute the 6pi in to x and 5pi, then do f(6pi)-f(5pi)
but wouldn't subtracting 6pi and 5pi give u the area?
how do you determine the max and min?
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