Question

Solve for t using natural logarithms.
7e^6t=10e^5t

Answer 1

how?

Answer 2

Oh, wait.

Answer 3

Let me show it.

Answer 4

thanks

Answer 5

it says to round 3 decimals to prob not 0

Answer 6

\[\Large e^{6t} = \frac{10}{7} e^{5t}\]

Answer 7

This equation thing isnt workin. just a sec.

Answer 8

okk

Answer 9

\[\Large 6t = \ln (\frac{10}{7} e^{5t})\]

Answer 10

and from there?

Answer 11

Thinkin.

Answer 12

thanks

Answer 13

wow, this is confusing.

Answer 14

Got it. :D

Answer 15

yayyyy

Answer 16

\[\Large 6t = \ln (\frac{10}{7}) + \ln e^{5t}\]
\[\Large 6t = \ln (\frac{10}{7}) + 5t\ln e\]
\[\Large 6t = \ln (\frac{10}{7}) + 5t(1)\]
\[\Large 6t = \ln (\frac{10}{7}) + 5t\]
\[\Large 6t-5t = \ln (\frac{10}{7})\]
\[\Large t = \ln(\frac{10}{7})\]

Answer 17

sure?

Answer 18

100%.

Answer 19

awesome! ill try it. thankss

Answer 20

Wow, thanks so much :)

Answer 21

Welcome.