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Solve 3x2 = 12x.
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3x^2 - 12x = 0 x(3x-12)=0 x = 0 or 3x-12 =0 x = 0 or x = 4
\[3 x^2=12x\] \[x^2=4x \therefore x^2-4x=0 \therefore x(x-4)=0 \therefore x= 0 or x =4\]
x=4
0 is also a solution
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