Question

[Related Rates]

Each side of a square is increasing at a rate of 6 cm/s. At what rate is the area of the square increasing when the area of the square is 16 cm^2?

Answer 1

At a glance, this look accurate. But no guarantees; while since I have touched this.

Answer 2

Agent, do you have an answer to this?

Answer 3

Area= x^2
dx/dt=6 cm/s
we have to find dA/dt when Area =16 or x=4
dA/dt=2x dx/dt
dA/dt= 2*4*6
dA/dt=48 cm^2/sec
area is increasing at the rate of 48cm^2/sec

Answer 4

ooh..woops i thought the area was 64 lol