Need help please. with cherrys on top :D
(x^3+x^2+2x-4÷(x-1)
Anwsers:
1. x2 + 2x + 4
2. x2 + x - 4
3. x2 + 4
10x^3-8x^2-12x/2x
Anwsers:
5x2 - 4x - 6
5x6 - 4x4 - 6x4
5x3 - 4x2 - 6x

Question

Need help please. with cherrys on top :D
(x^3+x^2+2x-4÷(x-1)
Anwsers: 
   1. x2 + 2x + 4 
   2. x2 + x - 4 
   3. x2 + 4 
10x^3-8x^2-12x/2x
Anwsers: 
5x2 - 4x - 6 
   5x6 - 4x4 - 6x4 
   5x3 - 4x2 - 6x

campbell_st · Answer

(x -1) is a factor as f(1) = 0. Use some polynomial division to solve it. Alternatively take (x -1) and multiply by each answer and see which gives the original equation

dumbcow · Answer

For 1st one use synthetic division:
the zero is 1

1| 1   1   2   -4
         1   2    4
   ------------
    1  2    4    0

The quotient is then : x^2 +2x +4

For the 2nd one just divide each term:
10x^3/2x = 5x^2
-8x^2/2x = -4x
-12x/2x = -6

--> 5x^2 -4x -6